A line has a slope of Negative three-fifths. Which ordered pairs could be points on a parallel line? Select two options. a (–8, 8) and (2, 2) b (–5, –1) and (0, 2) c (–3, 6) and (6, –9) d (–2, 1) and (3, –2) e (0, 2) and (5, 5)

Respuesta :

Options A and D are having a slope equal to -3/5.

Given that the slope of the line is -3/5.

That is, m = -3/5

We need to find which ordered pairs could be points on a parallel line.

What is the formula to find the slope of the line?

The formula for slope between two coordinates is m = (y₂ - y₁)/(x₂ - x₁).

Now,

Using (–8, 8) and (2, 2);

m = (2 - 8)/(2 - (-8))

⇒m = -6/10

m = -3/5

Using (–5, –1) and (0, 2);

m = (2 - (-1))/(0 - (-5))

m = 3/5

Using (–3, 6) and (6, –9);

m = (-9 - 6)/(6 - (-3))

⇒m = -15/9

m = -5/3

Using (–2, 1) and (3, –2);

⇒m = (-2 - 1)/(3 - (-2))

m = -3/5

Using (0, 2) and (5, 5);

m = (5 - 2)/(5 - 0)

m = 3/5

We know that the condition for parallel lines slope is [tex]m_{1} =m_{2}[/tex].

Therefore, options A and D are having a slope equal to -3/5.

To learn more about the slope of the line visit:

https://brainly.com/question/14511992.

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