The number of 1’s among the draws will be 155.
Binomial distributions consist of n independent Bernoulli trials.
The expected value is given as
E(X) = np
465 draws will be made at random with replacement from the box [0 0 1].
The number of 1’s among the draws will be
p = 1/3
n = 465
Then the expected value is given as
E(x) = 465 × 1/3
E(x) = 155
Learn more about binomial distribution here:
https://brainly.com/question/13609688
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