Respuesta :

Answer:

[tex]\frac{31}{8} or 3\frac{7}{8}[/tex]

Step-by-step explanation:

First, these 2 fractions are proper fractions, we will convert them into improper ones.

[tex]5\frac{2}{8} = \frac{42}{8}[/tex]

[tex]1\frac{3}{8} =\frac{11}{8}[/tex]

Now to subtract fractions, we must ensure the denominators are the same, which in this case is already the same, so we can subtract straightaway.

[tex]\frac{42}{8} - \frac{11}{8} \\=\frac{31}{8} or 3\frac{7}{8}[/tex]

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{5 \dfrac{2}{8} - 1 \dfrac{3}{8}}[/tex]

[tex]\mathsf{= \dfrac{5 \times 8 + 2}{8} - \dfrac{1 \times 8 + 3}{8}}[/tex]

[tex]\mathsf{= \dfrac{40 + 2}{8} - \dfrac{8 + 3}{8}}[/tex]

[tex]\mathsf{= \dfrac{42}{8} - \dfrac{11}{8}}[/tex]

[tex]\mathsf{= \dfrac{42 - 11}{8 - 0}}[/tex]

[tex]\mathsf{= \dfrac{42 - 11}{8}}[/tex]

[tex]\mathsf{= \dfrac{31}{8}}[/tex]

[tex]\mathsf{\approx 3 \dfrac{7}{8}}[/tex]

[tex]\huge\textsf{Therefore, your answer should be: \boxed{\mathsf{3 \dfrac{7}{8}}}}\huge\checkmark[/tex]

[tex]\huge\textsf{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040}[/tex]