Respuesta :
Answer:
The number that could not be a value of y if y = 4x² - 6 is -12.
Step-by-step explanation:
What is the value of y for a function of f(x)?
The value of y for which a function f(x) = y = 4x² - 6 can be determined by knowing the smallest value of y for which x is equal to zero.
So, from the equation y = 4x² - 6, we will replace the value of x with zero to determine the smallest value of y.
y = 4(0) - 6
y = 0 - 6
y = -6
Thus, any number smaller than -6 could not be a value of y for the equation y = 4x² - 6.
Therefore, we can conclude that the number that could not be a value of y if y = 4x² - 6 is -12.
SOLVING
[tex]\Large\maltese\underline{\textsf{A. What is Asked}}[/tex]
If x=-5, what is y is y=4-x²?
[tex]\Large\maltese\underline{\textsf{B. This problem has been solved!}}[/tex]
Put in the value of x.
[tex]\bf{y=4-(-5)^2}[/tex] | evaluate using Bodmas
[tex]\bf{y=4-25}[/tex] | subtract
[tex]\bf{y=-21}[/tex]
[tex]\cline{1-2}[/tex]
[tex]\bf{Result:}[/tex]
[tex]\bf{=y=-21}[/tex]
[tex]\LARGE\boxed{\bf{aesthetic \not1 \theta l}}[/tex]