Respuesta :

Answer:

The number that could not be a value of y if y = 4x² - 6 is -12.

Step-by-step explanation:

What is the value of y for a function of f(x)?

The value of y for which a function f(x) = y = 4x² - 6 can be determined by knowing the smallest value of y for which x is equal to zero.

So, from the equation y = 4x² - 6, we will replace the value of x with zero to determine the smallest value of y.

y = 4(0) - 6

y = 0 - 6

y = -6

Thus, any number smaller than -6 could not be a value of y for the equation y = 4x² - 6.

Therefore, we can conclude that the number that could not be a value of y if y = 4x² - 6 is -12.

SOLVING

[tex]\Large\maltese\underline{\textsf{A. What is Asked}}[/tex]

If x=-5, what is y is y=4-x²?

[tex]\Large\maltese\underline{\textsf{B. This problem has been solved!}}[/tex]

Put in the value of x.

[tex]\bf{y=4-(-5)^2}[/tex] | evaluate using Bodmas

[tex]\bf{y=4-25}[/tex] | subtract

[tex]\bf{y=-21}[/tex]

[tex]\cline{1-2}[/tex]

[tex]\bf{Result:}[/tex]

             [tex]\bf{=y=-21}[/tex]

[tex]\LARGE\boxed{\bf{aesthetic \not1 \theta l}}[/tex]