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A spherical ball is inflated so that it’s radius increases in the ratio 4:3. Find the ratio in which it’s volume is increased

Respuesta :

Answer:

64:27

Step-by-step explanation:

If the ratio between the old and new radius is described with the ratio: 4:3, then if the first radius was 3, then the new radius is 4.

Also if you multiply 3 by (4/3) it also equals 4

The volume of a sphere is described as:  [tex]\frac{4}{3} \pi r^{3}[/tex]

So let's plug in 3 and 4 and see their ratio.

[tex]\frac{\frac{4}{3}\pi 4^{3} }{ \frac{4}{3}\pi 3^{3} }} = \frac{4^{3} }{3^{3} } = \frac{64}{27}[/tex]

The answer is 64/27 or (4/3)^3

 

Answer:

by a factor of 64/27   or   64:27

Step-by-step explanation:

Volume of a sphere = 4/3  pi  r^3    

    now increase the radius  by 4/3      ( this is  4:3)

               new volume = 4/3 pi  (4/3 r)^3  

                                     = 64/27  *  4/3 pi r^3

so the original volume is increased by  64/27