The term can also be written as:

The correct expansion is the one in option b:
[tex]Log_9(\frac{6}{11}) = Log_9(6) - Log_9(11)[/tex]
Here we must use the logarithmic property:
[tex]Log(a) -Log(b) = Log(\frac{a}{b})[/tex]
Our expression in this case is:
[tex]Log_9(\frac{6}{11})[/tex]
Using the above property, we can rewrite the expression as:
[tex]Log_9(\frac{6}{11}) = Log_9(6) - Log_9(11)[/tex]
From this, we conclude that the correct option is B.
If you want to learn more about logarithms:
https://brainly.com/question/13473114
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