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A basketball player passes the ball to a teammate. The ball reaches a velocity of 5.5 m/s, 2 seconds after the ball leaves the player’s hands. What is the acceleration of the ball during those two seconds?

Respuesta :

saadatk

Answer:

acceleration = 2.25 m/s²

Explanation:

[tex]a = \frac{v - u}{t}[/tex]

where:

a = acceleration (?)

v = final velocity (5.5 m/s)

u = initial velocity (0 m/s, because the ball starts from rest)

t = time taken (2s).

Using the formula:

acceleration = [tex]\frac{5.5 - 0 }{2}[/tex]

                     = 2.75 m/s²

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