there are three brothers amir balu and caleb. Amirs age is half of calebs and balus age is 3/4 of calebs. In five years the sum of Amir's age and Balus age will be 16 more than Calebs age How old is each brother now.

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ashishdwivedilVT ashishdwivedilVT · Answer 1 · 2022-07-12T17:09:12+02:00

The age of the brothers Caleb, Amir and Balu is 44 years, 22 years, and 33 years respectively.

An equation is a mathematical statement with an 'equal to=' symbol between two expressions that have equal values.

Here, Let the age of the Caleb's be x years.

then age of Amir's be x/2 years.

also age of Balu's be 3x/4 years.

In 5 years,

Caleb's age = (x+5) years

Amir's age = (x/2 + 5) years

Balu's age = (3x/4 + 5) years

Now, According to question;

Amir's age + Balu's age = 16 + Caleb's age

(x/2 + 5) + (3x/4 +5) = 16 + (x + 5)

x/2 + 3x/4 - x = 16 + 5 - 5 - 5

(2x + 3x - 4x)/4 = 11

x/4 = 11

x = 4 X 11

x = 44

Now, Caleb's age = 44 years

Amir's age = 44/2 = 22 years

Balu's age = 3X44/4 = 33 years

Thus, the age of the brothers Caleb, Amir and Balu is 44 years, 22 years, and 33 years respectively.

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