Respuesta :
1.98 g many grams of [tex]BaCrO_4[/tex] can be formed if a solution containing 1.63 grams [tex]BaCl_2[/tex] is added to a solution containing 2.40 grams of [tex]Na_2CrO_4[/tex].
What are moles?
A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
[tex]BaCl_2 + Na_2CrO_4[/tex][tex]\rightarrow[/tex] [tex]BaCrO_4 + 2 NaCl[/tex]
Mass of [tex]BaCl_2[/tex] = 1.63 g
Molar mass of [tex]BaCl_2[/tex] = 208.23 g/mol
Moles of [tex]BaCl_2[/tex] = 1.63/ 208.23 = 0.0078 mol
Mass of [tex]Na_2CrO_4[/tex] = 2.40 g
Molar mass of [tex]Na_2CrO_4[/tex] = 161.97 g/mol
Moles of [tex]Na_2CrO_4[/tex]= [tex]\frac{mass}{molar \;mass}[/tex]
Moles of [tex]Na_2CrO_4[/tex] =[tex]\frac{2.40}{161.97 }[/tex]
=0.0148 mol
From the balanced equation mole ratio of [tex]BaCl_2[/tex] : [tex]Na_2CrO_4[/tex] = 1:1
But here, moles of [tex]BaCl_2[/tex] < moles of [tex]Na_2CrO_4[/tex]
Therefore, [tex]BaCl_2[/tex] is the limiting reagent.
From the balanced equation above it is clear that 1 mol of[tex]BaCl_2[/tex] reacts with 1 mol of [tex]Na_2CrO_4[/tex] to give1 mol of [tex]BaCrO_4[/tex].
Therefore, 0.0078 mol of [tex]BaCl_2[/tex] will produce 0.0078 mol of [tex]BaCrO_4[/tex].
Molar mass of [tex]BaCrO_4[/tex] = 253.37 g/mol
Therefore, the mass of [tex]BaCrO_4[/tex] can be formed = 0.0078 x 253.37 = 1.98 g
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