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In the preparation of the soap above, a student dissolved 5 g of NaOH in 25 mL water and added 10 mL palm kernel oil (density: 0.997 g/cm3). The mixture was heated and boiled with 20 mL of water, followed by addition of NaCl to the soap solution. At the end of the experiment, the student obtained 6.2 g of soap What is the percentage yield of the soap?

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mickymike92

The  Percent yield of  soap is 17.8%

What is the percent yield of soap?

Percent yield is given as follows:

  • Percent yield = actual yield/expected yield * 100%

The actual yield of soap = 6.2 g

The expected yield is determined from the equation of the reaction.

The equation of the reaction is given as follows:

NaOH + CH₃(CH₂)₁₄COOH ----> CH₃(CH₂)₁₄COONa + H₂O

Molar mass of (palm kernel oil) CH₃(CH₂)₁₄COOH = 256 g/mol

Molar mass of NaOH = 40 g/mol

Molar mass of (soap) CH₃(CH₂)₁₄COONa = 278 g/mol

Mass of palm kernel oil = 9.9 g

Expected mass of soap = 5/40 * 278 = 34.75 g

Percent yield = 6.2/34.75 * 100 = 17.8%

Therefore, the Percent yield of  soap is 17.8%

Learn more about percent yield at: https://brainly.com/question/14714924

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