a) mg[tex]\frac{1}{2}[/tex] = [tex]ml^\frac{2}{3}[/tex] * ω
b)ω = [tex]\frac{3g}{2l}[/tex]
c)14.7 the magnitude of the initial acceleration of the end B when the string is cut.
What is Acceleration?
Acceleration is the rate of change of the velocity of an object with respect to time.
Given
A rod of length 56.0 cm and mass 1.40 kg is suspended by two strings which are 42.0 cm long, one at each end of the rod.
When the string is cut rod rotates about other end.
Let's take momentum equation about that end:
mg*[tex]\frac{1}{2}[/tex] = Iω [I = [tex]ml^\frac{2}{3}[/tex]]
a) mg[tex]\frac{1}{2}[/tex] = [tex]ml^\frac{2}{3}[/tex] * ω
Angular acceleration:
b)ω = [tex]\frac{3g}{2l}[/tex]
c)Acceleration of end B:
a = lω= [tex]\frac{3g}{2}[/tex] =[tex]\frac{3*9.8}{2}[/tex]
a = 14.7 [g=9.8]
Learn more about Acceleration here:
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