Answer:
[tex] \boxed{\sf{x = \frac{5 \pm \sqrt{97} }{12} }}[/tex]
Step-by-step explanation:
[tex]\sf{5x = 6 {x}^{2} - 3 }[/tex]
[tex]\sf{0 = 6 {x}^{2} - 3 - 5x }[/tex]
[tex]\sf{0 = 6 {x}^{2} - 5x - 3 }[/tex]
[tex] \sf{x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} }[/tex]
[tex]\sf{x = \frac{ - ( - 5) \pm \sqrt{ { - 5}^{2} - 4(6)( - 3)} }{2(6)} }[/tex]
[tex]\sf{x = \frac{5 \pm \sqrt{ 25 + 72} }{12} }[/tex]
[tex]\sf{x = \frac{5 \pm \sqrt{97} }{12} }[/tex]