The volume of the cylinder whose radius is 5x-1 unit is 25x²πh + πh - 10xπh.
Suppose that the radius of the considered right circular cylinder is 'r' units.
And let its height be 'h' units.
Then, its volume is given as:
[tex]V = \pi r^2 h \: \rm unit^3[/tex]
The right circular cylinder is the cylinder in which the line joining centre of the top circle of the cylinder to the centre of the base circle of the cylinder is perpendicular to the surface of its base, and to the top.
Given that the radius of the cylinder is (5x-1), while the height of the cylinder is h. Therefore, the volume of the cylinder is,
The volume of the cylinder = π × (5x-1)² × h
= (25x² + 1 - 10x)πh
= 25x²πh + πh - 10xπh
Hence, the volume of the cylinder is 25x²πh + πh - 10xπh.
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