Create two radical equations: one that has an extraneous solution, and one that does not have an extraneous solution. Use the equation below as a model:

[tex]a\sqrt{x+b} +c=d[/tex]

Respuesta :

The radical equation that has an extraneous solution is 5✓x + 10 - 15 = 30

How to calculate the equation?

Based on the information given, the radical equation that has an extraneous solution is 5✓x + 10 - 15 = 30.

This will be:

5✓x + 10 - 15 = 30

Collect like terms

5✓x = 30 - 10 + 15

5✓x = 35

✓x = 35/5

✓x = 7

x = 7² = 49

The equation that does not have an extraneous solution will be ✓x + 1 + 7 = 4. Here, ✓x = -4 and has no solution.

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