Respuesta :
25.54 g of diethyl ether would you obtain from 41.8 g of ethyl alcohol if the per cent yield of the reaction is 76.6 %.
What are moles?
A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Step 1: Write the balanced equation
2 CH₃CH₂OH ⇒ CH₃CH₂OCH₂CH₃ + H₂O
Step 2: Calculate the moles corresponding to 41.8 g of CH₃CH₂OH
The molar mass of CH₃CH₂OH is 46.07 g/mol.
41.8 g × 1 mol ÷ 46.07 g = 0.90.
Step 3: Calculate the theoretical moles of CH₃CH₂OCH₂CH₃ produced
The molar ratio of CH₃CH₂OH to CH₃CH₂OCH₂CH₃ is 2:1. The moles of CH₃CH₂OCH₂CH₃ theoretically produced are 1/2 × 0.90 mol = 0.45
Step 4: Calculate the real moles of CH₃CH₂OCH₂CH₃ produced
The percent yield of the reaction is 85%.
0.45 mol × 76.6% = 0.3447 mol
Step 5: Calculate the mass corresponding to 0.3447 moles of CH₃CH₂OCH₂CH₃
The molar mass of CH₃CH₂OCH₂CH₃ is 74.12 g/mol.
34.47 mol × 74.12 g/mol = 25.549164 g
Hence, 25.54 g of diethyl ether would you obtain from 41.8 g of ethyl alcohol if the per cent yield of the reaction is 76.6 %.
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