The pH of the solution is obtained as 2.23.
What is the pKa?
The pKa shows the extent to which an acid is dissociated in solution. Now we have;
HCOOH(aq) + H2O(l) ⇔ HCOO-(aq) + H30+(aq)
Ka = [HCOO-] [ H30+]/[ HCOOH]
But = [HCOO-] = [ H30+] = x
Ka = x^2/[HCOOH]
x = √Ka [HCOOH]
x = √0.19 * 1.8×10−4
x = 5.8 * 10^-3
pH = - log (5.8 * 10^-3)
pH = 2.23
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