Answer:
- 0.57138096 M
- 0.571mol
- 0.571 M NaHCO3
- 0.571 mol/NaHCO3
(these are just different ways to identify the units but they all work and mean the same thing)
Explanation:
- molarity is measured by the ratio of the moles of a solute per liters of a solution
- the formula for molarity is: [tex]M = \frac{mol (s) solute}{L solution}[/tex]__________________________________________________________
- first, you need to convert 250mL to L so, [tex]250/1000=0.25[/tex]
- when it comes to converting g to mol you can do it in a separate equation but i prefer to do it all in one equation
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- so the equation for this specific problem would be set up like this:[tex]\frac{12.0g}{.25L} x \frac{1mol}{84.007 g} = x[/tex]
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- now to actually solve it:
[tex]\frac{12.0g}{.25L} x \frac{1mol}{84.007 g} = \frac{12.0}{21.00175} = 0.57138096(or)/0.571mol/0.571 M NaHCO3/(0.571 mol/NaHCO3)[/tex]
hope this helps :)
