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In a filtration experiment 25cm of a solution of a sodium hydroxide contain 8g per litre was required for complete neutralization of 0.245g of a diabasic acid. Calculate the relative molecular mass of the acid (Na= 23, O=16,H=1)

Respuesta :

The relative molecular mass of an element is a proportion of the mass of the unified amu. The relative molecular mass of sodium hydroxide is 40.

What is molecular mass?

The molecular mass of a substance is an addition of the individual masses of the element that makes the compound.  

Moles of NaOH = 8 mole

Molarity = 0.2 M

Moles of sodium hydroxide in 25 cm³: 25 × 0.2 = 0.005 moles

The mole ratio between the two moles:

0.2 ÷ 0.005 = 40

Therefore, 40 is the relative molecular mass of the acid.

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