Answer:
[tex]\frac{1}{2}[/tex]
Step-by-step explanation:
sin([tex]cos^{-1}[/tex] [tex]\frac{\sqrt{3} }{2}[/tex] )
using the sides of the 30- 60- 90 triangle
with legs 1, [tex]\sqrt{3}[/tex] and hypotenuse 2 , then
[tex]cos^{-1}[/tex] [tex]\frac{\sqrt{3} }{2}[/tex] = 30° and
sin30° = [tex]\frac{1}{2}[/tex]
