A boy is pushing a 60 KG box along the floor by applying a horizontal force of 115 and the box is accelerating at a rate of 0.5 m/s^2 what is the coefficient of kinetic friction between the box and the floor

Respuesta :

The coefficient of kinetic friction between the box and the floor will be 3.83.

What is the friction force?

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

it is defined as the product of the coefficient of friction and normal reaction.

Given data;

m is the mass of a boy = 60 kg

Horizontal force,f = 115 N

The coefficient of kinetic friction between the box and the floor,μ

Acceleration,a = 0.5 m/s²

The friction force is found as;

f = μN

The normal force is found as;

N =ma

f=μma

115 N = μ × 60 kg × 0.5 m/s²

μ = 3.83

Hence, the coefficient of kinetic friction between the box and the floor will be 3.83.

To learn more about the friction force refer to the link;

https://brainly.com/question/1714663

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