Answer:
A. 0.23 ms⁻²
Explanation:
Using the equation:
v² = u² + 2as
where:
v = final velocity (85 kmh⁻¹ = 85 x 0.278 = 23.6 ms⁻¹)
u = initial velocity (0 ms⁻¹)
a = acceleration (? ms⁻²)
s = displacement (1.20 km = 1.2 x 1000 = 1200 m),
[tex](23.6)^2 = (0)^2 + 2 (a) (1200)[/tex]
⇒ [tex]a = \frac{23.6^2}{2(1200)}[/tex]
⇒ a = 0.23 ms⁻²
