If we want to replace a input and display an output greater than 10⁹ in Susan's calculator, then we want at least 3 consecutive operations.
How to determine a power by a "cubing" key
In accordance with the statement, Susan's calculator performs the following operation by pressing the "cubing" key:
x → x³
If we need to display a number that is greater than 10⁹, then we need to press the "cubing" key as many as needed. By algebra we have the following property for a power:
[tex](x^{m})^{n} = x^{m\cdot n}[/tex] (1)
Since we have a "cubing" key and we are supposed to make consecutive operation, we derive the following operation:
x → [tex]x^{3^{i}}[/tex], where i is the number of consecutive "cubing" operations.
If we want to replace a input and display an output greater than 10⁹ in Susan's calculator, then we want at least 3 consecutive operations.
Remark
The statement presents typing mistakes, correct form is shown below:
Susan's calculator has a key that replaces the number displayed with its cube. If a³, is displayed, how many time must Susan press the "cubing" key to display a number that is greater than 10⁹.
To learn more on real numbers: https://brainly.com/question/551408
#SPJ1
