The horizontal component of the train's speed is 5.54 m/s and the vertical component's of the train's speed is 6.85 m/s.
The horizontal component of the train's speed is calculated as follows;
Vx = V cosθ
where;
Vx = 8.81 m/s x cos(51)
Vx = 5.54 m/s
Vy = 8.81 m/s x sin(51)
Vy = 6.85 m/s
Thus, the horizontal component of the train's speed is 5.54 m/s and the vertical component's of the train's speed is 6.85 m/s.
The complete question is below:
a train travels 8.81 m/s in a -51.0 direction. the train accelerates 2.23 m/s². Find the horizontal and vertical component of the train's speed.
Learn more about horizontal speed here: https://brainly.com/question/24949996
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