Answer:
(0, 0)
Step-by-step explanation:
Ok so you have the equation: [tex]y = log_2{(x+2)}-1[/tex]. To find the zero you simply set the y equal to zero and then solve for x
[tex]0 = log_2{(x+2)}-1[/tex]
Add 1 to both sides
[tex]1 = log_2{x+2}[/tex]
Rewrite the equation in exponential form:
[tex]2^1=x+2[/tex]
Subtract 2 from both sides
[tex]0 = x[/tex]
So the zero of the function is at the origin (0, 0)
