Answer:
[tex]x = \frac{-1 \pm \sqrt{33}}{4}[/tex]
Step-by-step explanation:
Hello!
We can solve the quadratic by using the Quadratic Formula.
Standard form of a Quadratic: [tex]ax^2 + bx +c = 0[/tex]
Quadratic Formula: [tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
Given our equation: [tex]2x^2 + x - 4 = 0[/tex]
Plug in the values into the quadratic formula to solve.
Solve the quadratic
- [tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
- [tex]x = \frac{-1 \pm \sqrt{1^2 - 4(2)(-4)}}{2(2)}[/tex]
- [tex]x = \frac{-1 \pm \sqrt{1 + 32}}{4}[/tex]
- [tex]x = \frac{-1 \pm \sqrt{33}}{4}[/tex]
The solution to the quadratic is [tex]x = \frac{-1 \pm \sqrt{33}}{4}[/tex].
