The number of formula units in 116 g of NaCl is 1.204×10²⁴ formula units
Avogadro's hypothesis
1 mole of NaCl = 6.02×10²³ formula units
But
1 mole of NaCl = 58 g
Thus,
58 g of NaCl = 6.02×10²³ formula units
How to determine the formula units in 116 g of NaCl
58 g of NaCl = 6.02×10²³ formula units
Therefore,
116 g of NaCl = (116 × 6.02×10²³) / 58
116 g of NaCl = 1.204×10²⁴ formula units
Thus, 1.204×10²⁴ formula units are present in 116 g of NaCl
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