3
its out
n
A mom walks into her child's room and finds clothes all over the floor. 20% of the clothes are
clean. She randomly picks up 5 articles of clothing.
1. We can expect 1
2. The standard deviation is 25
3. Because the distribution has a
r
O
5
, the distribution is close to skewed right (positive)

n-
4. Use the probability formula P(r) =n Crp'q" to create a binomial distribution table.
Probability formula
Round to the tenth, if necessary.
6
✔ CO
Dirty Room
out of 5
articles of clothing to be clean.
x. (Round to the nearest tenth, if necessary.)
probability of success (P(S)) that is
5
✓.2 ✓
0
small (closer to 0)
P(r)
Enter the probability only.
Round to the 4th decimal place, if
necessary.
.6
?

Respuesta :

The probability computed shows that we can expect 1 out of 5 clothes to be clean.

How to calculate the probability?

From the information given, it was stated that 20% of the clothes are clean. Therefore, the probability of clean clothes will be:

= 20% = 1/5.

Therefore, one out fo five clothes are clean.

The standard deviation will be:

= ✓npq

where,

n = 5

p = 0.20

q = 1 - 0.20 = 0.80

SD = ✓(5 × 0.20 × 0.80)

= ✓0.80

= 0.09

The distribution is close to symmetric.

The binomial distribution table will be:

0 = (0.20)^0 (0.80)^5 = 0.3277

1 = (0.20)¹ (0.80)⁴ = 0.4096

2 = (0.20)² (0.80)³ = 0.2040

3 = (0.20)³ (0.80)² = 0.0512

4 = (0.20)⁴ (0.80)¹ = 0064

5 = (0.20)^5 (0.80)^0 = 0.0003

Learn more about probability on:

brainly.com/question/24756209

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