What is the molality, m, of a solution made by adding 8.21 g of solid naphthalene, C10H8, to 27.92 g of liquid benzene, C6H6? The molar mass of naphthalene = 128.2 g/mol and benzene = 78.1 g/mol.

Respuesta :

4.21×[tex]10^{-4}[/tex] Molal is the molality, m, of a solution made by adding 8.21 g of solid naphthalene, [tex]C_{10}H_8[/tex], to 27.92 g of liquid benzene,[tex]C_6H_6[/tex].

What are moles?

A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

[tex]Molality = \frac{Moles \;solute}{Solvent \;in \;kg}[/tex]

Moles of naphthalene=[tex]\frac{mass}{molar \;mass}[/tex]

Moles of naphthalene[tex]=\frac{8.21 g}{128.2 g/mol}[/tex]

=0.064

Moles of benzene[tex]=\frac{mass}{molar \;mass}[/tex]

Moles of benzene[tex]=\frac{27.92 g}{78.1 g/mol}[/tex]

=0.357

Total mole of solute= 0.064+0.357=0.421

[tex]Molality = \frac{Moles \;solute}{Solvent \;in \;kg}[/tex]

[tex]Molality = \frac{0.421 }{1000}[/tex]

Molality = 4.21×[tex]10^{-4}[/tex] Molal

Hence, 4.21×[tex]10^{-4}[/tex] Molal is the molality, m, of a solution made by adding 8.21 g of solid naphthalene, [tex]C_{10}H_8[/tex], to 27.92 g of liquid benzene, [tex]C_6H_6[/tex].

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