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A car with a mass of 1080 kg is traveling in a mountainous area with a constant speed of 69.6 km/h. The road is horizontal and flat at point A, horizontal and curved at points B and C.
1. The radii of curvatures at B and C are: rB = 130 m and rC = 115 m. Calculate the normal force exerted by the road on the car at point A.
Normal Force = 1.-6x10^4 N
2. Now calculate the normal force exerted by the road on the car at point B.

A car with a mass of 1080 kg is traveling in a mountainous area with a constant speed of 696 kmh The road is horizontal and flat at point A horizontal and curve class=

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(1) The normal force exerted by the road on the car at point A is 1.06 x 10⁴ N

(2) The normal force exerted by the road on the car at point B is 7,495.8 N.

Normal force at point A

Fn(A) = mg

where;

  • m is mass of the car
  • g is acceleration due to gravity

Fn(A) = 1080 x 9.81

Fn(A) = 1.06 x 10⁴ N

Normal force exerted by the road on the car at point B

The normal force exerted by the road on the car at point B is calculated as follows;

Fn = Fn(A) - mv²/r

where;

  • Fn(A) is normal force at point A
  • m is mass of the car
  • r is radius of curve B
  • v is velocity of the car, 69.6 km/h = 19.33 m/s

Fn = 1.06 x 10⁴ - (1080 x 19.33²)/(130)

Fn = 7,495.8 N

Thus, the normal force exerted by the road on the car at point A is 1.06 x 10⁴ N and the normal force exerted by the road on the car at point B is 7,495.8 N.

Learn more about normal force here: https://brainly.com/question/14486416

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