Respuesta :
535.8 L volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.
What is an ideal gas equation?
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Given:
[tex]C(s) + O_2(g)[/tex] ⇒[tex]CO_2(g)[/tex]
1 mole of [tex]CO_2(g)[/tex] is formed from 1 mole of charcoal, that means 1 mole of [tex]CO_2(g)[/tex] is formed from 12 g of charcoal.
1 lbs = 453.592 grams
6.75 lbs = 6.75 x 453.592 =3061.746g
So, [tex]CO_2(g)[/tex] formed from 3061.746g of charcoal is:
=[tex]\frac{1}{12}[/tex] x 3061.746g
=255.14 mol.
Now, at STP, the volume of 1 mol of gas =22.4 L
Volume of 255.14 mol of [tex]CO_2(g)[/tex] = 255.14 x 22.4 L
Volume of 255.14 mol of [tex]CO_2(g)[/tex] = 535.8 L
Hence, 535.8 L volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.
Learn more about the ideal gas here:
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