An airplane travels 640 miles from Topeka to Houston in 3.2 hours, going against the wind. The return trip is with the wind, and takes only 2 hours. Find the rate of the airplane with no wind. Find the rate of the wind.
A) The airplane flies at 210 mi/h with no wind. The rate of the wind is 50 mi/h.
B) The airplane flies at 210 mi/h with no wind. The rate of the wind is 60 mi/h.
C)The airplane flies at 260 mi/h with no wind. The rate of the wind is 60 mi/h.
D)The airplane flies at 260 mi/h with no wind. The rate of the wind is 50 mi/h.

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raphealnwobi raphealnwobi · Answer 1 · 2022-07-11T17:26:23+02:00

The airplane flies at 260 mi/h with no wind, while the rate of the wind is 60 mi/h.

An equation is an expression that shows the relationship between two or more numbers and variables.

Let a represent the rate of the airplane with no wind. and b the rate of the wind, hence:

(a - b)3.2 = 640

a - b = 200 (1)

Also:

(a + b)2 = 640

a + b = 320 (2)

The solution to equation 1 and 2 is:

a = 260, b = 60

The airplane flies at 260 mi/h with no wind, while the rate of the wind is 60 mi/h.

Find out more on equation at: https://brainly.com/question/2972832

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