MATH: FINDING HALF LIFE PT 2..HELP!

The half life of the radioactive Rutherford-265 is;
13.1 hours.
It follows from the task content that the given function represents the decay function of the radioactive material. Since half-life corresponds to the point at which only half of the starting material remains, hence we have;
(1/2) = e ^(-0.053t)
By taking the natural log of both sides, we have;
-0.6931 = -0.053t
Hence, t = -0.6931/ -0.053 = 13.1 hours.
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