The solution to the given linear equation are -4 and 2
Quadratic equations are equations that has a leading degree of 2. Given the expression below
(x-3)(x+1)=5
Expand
x^2+x - 3x - 3 = 5
x^2 - 2x - 8 =0
Factorize
x^2 + 4x - 2x - 8= 0
x(x+4)-2(x+4) = 0
x = -4 and 2
Hence the solution to the given linear equation are -4 and 2
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