A sample of gas has temperature of 372 K and pressure of 3.8 ATM. If the temperature is increased to 550 K, what is the new pressure?

Respuesta :

Answer: The correct answer is 5.6atm.

Explanation: Since we only have information on the pressure and temperature, we will use Gay-Lussac's Law: [tex]\frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }[/tex]. Now that we have the formula, let's plug in our given information!

[tex]\frac{3.8atm}{372K} =\frac{P_{2} }{550K}[/tex]

We must find the value [tex]P_{2}[/tex]. To do this, we will write a stoichiometric equation to solve this.

[tex]P_{2} =\frac{3.8atm*550K}{372K}[/tex]

Let's input the numbers into a scientific calculator to get our answer!

[tex]P_{2} =\frac{3.8atm*550K}{372K}=5.6 atm[/tex]

Given all of this work, the value [tex]P_{2}[/tex] equals 5.6 atm.

I hope this helps! Pls give brainliest!! :)