Answer:
V2 = 0.941 L
Explanation:
This follows the Charles' law, a gas law.
Using this eq [tex]\frac{V1}{T1} =\frac{V2}{T2}[/tex]
From the given, the missing variable is V2
[tex]\frac{752 ml}{298 K} =\frac{V2}{373 K}[/tex], change ml to SI unit of Volume (L)
752 ml = 0.752 L
[tex]\frac{752 L}{298 K} =\frac{V2}{373 K}[/tex], then cross multiply
[tex]280.496 L (K) =298K (V2)[/tex]
[tex]\frac{280.496 L (K) }{298K} = (V2)[/tex]
[tex]V2 = 0.941 L[/tex]
