Answer:
[tex]\displaystyle 2[/tex]
Step-by-step explanation:
[tex]\displaystyle y = Acos(Bx - C) + D[/tex]
When working with a trigonometric equation like this, always remember the information below:
[tex]\displaystyle Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A|[/tex]
So, the first procedure is to find the period of this graph, and when calculated, you should arrive at this:
[tex]\displaystyle \boxed{\frac{1}{2}} = \frac{2}{4\pi}\pi[/tex]
You will then plug this into the frequency formula, [tex]\displaystyle T^{-1} = F.[/tex] Look below:
[tex]\displaystyle \frac{1}{2}^{-1} = F \\ \\ \boxed{2 = F}[/tex]
Therefore, the frequency of motion is two hertz.
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