How do you solve this?

Answer:
No solutions
Step-by-step explanation:
First ADD 4 /(X+4) to both sides of the equation to get
( x+4)/ (x+ 4) = 3
1 = 3 ???? There are no solutions
[tex]\dfrac{x}{x+4}=3-\dfrac{4}{x+4}\qquad(x\not=-4)\\\\x=3(x+4)-4\\x=3x+12-4\\2x=-8\\x=-4[/tex]
Which contradicts initial assumption, therefore [tex]x\in\emptyset[/tex].