I have tried this problem multiple times now and don't get the correct answer. Please help!

The confidence interval is (-1.1059, 7.70459).
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A confidence interval is the mean of your estimate plus and minus the variation in that estimate.
The sample mean is M=3.3
The sample size is N=44
So, σM= s/√N = 16.6/ √44
= 16.6/ 6.633
= 2.621
and, the degree of freedom
df= n-1
=44-1
=43
So, The t-value for a 90% confidence interval and 43 degrees of freedom is t=1.681.
Now, Margin of error = 2.261* 1.681 = 4.4059
Now, the lower and upper bound of the confidence interval are:
LL = 3.3- 4.40459 = -1.1059
UL = 3.3+ 4.40459 = 7.70459
Hence, the confidence interval is (-1.1059, 7.70459).
Learn more about this concept here:
https://brainly.com/question/14089556
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