Respuesta :
(a) The magnitude of the static friction force is 145 N
(b) The minimum possible value of static friction is 0.44.
What is the friction force?
It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).
it is defined as the product of the coefficient of friction and normal reaction.
Given data;
The horizontal force exerted, F =145 N
Mass of crate,m =33.2 kg.
The velocity of the crate,v =0 m/sedc
The magnitude of the static friction force, [tex]\rm f_s[/tex] =? N
The minimum possible value of the coefficient of static friction between the crate and the floor is,
Normal reaction,N = mg
a)
The forces acting on the crate are balanced since it is at rest; as a result, the horizontal force is equal to the frictional force, f:
F = [tex]\rm f_s[/tex] = 145 N
(b)
The following equations provide the greatest allowable force of friction between the floor and the crate:
[tex]\rm f_{min}= \mu_s N \\\\ \rm f_{min}= \mu_s mg \\\\[/tex]
The force applied to the box must be less than or equal to the maximum force of friction in order for it to stay at rest.
[tex]\rm f \leq f_{min} \\\\ f \leq \mu_s mg \\\\ 145 \leq \mu_s (33.2 \times 9.81 ) \\\\ \mu_s \geq 0.44[/tex]
Hence, the magnitude of the static friction force and minimum possible value of the coefficient of static friction between the crate and the floor will be 145 N and 0.44.
To learn more about the friction force refer to the link;
https://brainly.com/question/1714663
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