The daughter's age in 6 years time is 20
How to determine their ages?
Let their current age be x and y
So, we have:
x = 3y
7 years ago, we have:
x - 7 : y - 7 = 5 : 1
Express as fraction
[tex]\frac{x - 7}{y - 7} = \frac 51[/tex]
Cross multiply
x - 7 = 5y - 35
This gives
x = 5y - 28
Substitute x = 3y in x = 5y - 28
3y = 5y - 28
Evaluate the like terms
2y = 28
Divide by 2
y = 14
In 6 years time, we have:
y + 6 = 20
Hence, the daughter's age in 6 years time is 20
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