The expressions for the next two odd numbers after 2n -1 are; 2n +1 and 2n +3.
If follows from the task content that the expressions for the next two odd numbers after 2n-1 are required.
Since odd numbers are have difference 2, it follows that the next 2 odd numbers must be obtained by adding each time. Hence, we have, 2n +1 and 2n +3.
The sum is a multiple of 3 because; 2n -1 + 2n +1 + 2n +3 = 6n +3 = 3(2n+1).
Hence, the sum is multiples of 3.
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