Respuesta :
Answer:
Point-slope form of equation given as [tex]$y-2=-2(x+2)$[/tex].
Slope-intercept form of equation is given as [tex]$y=-2 x-2$[/tex].
Step-by-step explanation:
In the question, it is given that the slope of a line is -2 and it passes from (-2,2).
It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.
To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.
Step 1 of 2
Passing point of the line is (-2,2).
Hence, [tex]$x_{1}=-2$[/tex] and
[tex]$y_{1}=2 \text {. }$[/tex]
Also, the slope of the line is -2.
Hence, m=-2
Substitute the above values in point-slope form of equation given by [tex]$y-y_{1}=m\left(x-x_{1}\right)$[/tex]
[tex]$\begin{aligned}&y-y_{1}=m\left(x-x_{1}\right) \\&y-2=-2(x-(-2) \\&y-2=-2(x+2)\end{aligned}$[/tex]
Hence, point-slope form of equation given as y-2=-2(x+2).
Step 2 of 2
Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.
[tex]$\begin{aligned}&y-2=-2(x+2) \\&y-2=-2 x-4 \\&y=-2 x-4+2 \\&y=-2 x-2\end{aligned}$[/tex]
Hence, slope-intercept form of equation is given as y=-2x-2.
