Respuesta :
The minimum sample size needed in the research of systolic blood pressure is 68.
Given standard deviation=25 mm Hg, confidence level=90%, Estimation =5 mm Hg.
We have to first find the level of alpha which is known as error.
α=(1-0.9)/2
=0.05
Now we have to find z in the z table as such z has a p value of 1-α,that is z with a p value of 1-0.05
=0.95 ,so Z=1.645.
now finding the margin of error, which is as under:
[tex]M=z st/\sqrt{n}[/tex]
in which st is standard deviation and the n is sample size of population.
By assuming the standard deviation of 25 mm Hg we get values as under:
n is sample size.
[tex]M=z* st/\sqrt{n}[/tex]
[tex]5=1.645*25/\sqrt{n}[/tex]
[tex]5\sqrt{n}=1.645*25\\[/tex]
dividing both sides by 5
[tex]\sqrt{n}=1.645*5[/tex]
squaring both sides we get
n=67.65.
Hence the sample size needed by the researcher is 68.
Learn more about margin of error at https://brainly.com/question/24289590
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The given question is incomplete as it should includes :
standard deviation= 25mm Hg
Confidence level=90%
Estimation 5 mm Hg of u.