The margin of error for a 95% confidence interval for the population proportion is 0.0815.
Given sample size=60 and confidence interval of 95%.
We have to calculate margin of error for a confidence interval of 95%.
Margin of error is the difference between actual values and calculated values. Margin of error is a part of z test.
We have been given sample size=60.
8 people have received help from their parents from the sample.
p=8/60=0.13
which is sample proportion.
z=1-0.13
=0.87
To calculate standard error=[tex]\sqrt{p*z/n}[/tex]
=[tex]\sqrt{0.13*0.8/60}[/tex]
=0.0416
at 95% confidence interval
z(α/2)=1.96
therefore margin of error=1.96*0.0416
=0.081536
=0.0815
Hence the margin of error for 95% confidence interval is 0.0815
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