Respuesta :

Mass of liquid present in the container:

Yes, the liquid will be present, and of 1.2481 g

Calculation:

Given:

Volume = 1.5L

Temperature = 25 + 273 = 298K

P = 23.76 torr = 0.0312 atm

Using the ideal gas equation:

PV = nRT

Where:

  • P: Pressure
  • V: Volume
  • n: number of moles
  • R: gas constant = 0.0821 L atm [tex]K^{-1}[/tex] [tex]mol^{-1}[/tex]
  • T: Temperature

making n subject of formula:

n = [tex]\frac{PV}{RT}[/tex]

By putting all the values in the given equation, we get,

n = 0.0312 x 1.5 / 0.0821 x 298

n = 0.0019 moles

So, 0.00189 are moles of water in the vapor

Now, subtract  1.25g of water from moles of water vapor, and we will get the mass of the liquid left,

1.25 - 0.0019 = 1.2481 g

Learn more about the ideal gas equation here,

https://brainly.com/question/14478699

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