A microwaveable cup-of-soup package needs to be constructed in the shape of cylinder to hold 450 cubic centimeters of soup. The sides and bottom of the container will be made of styrofoam costing 0.03 cents per square centimeter. The top will be made of glued paper, costing 0.08 cents per square centimeter. Find the dimensions for the package that will minimize production cost.

Respuesta :

The  dimensions of the microwave cup-of-soup package are:

Radius = 3.39cm, and Height = 9.27cm.

Computed using differentiation.

The microwave cup-of-soup package is in the shape of a cylinder.

Thus, its volume can be shown as, V = πr²h, where r is its radius in cm and h is its height in cm.

The volume is given to be 450 cm³.

Thus, we can say that,

πr²h = 450,

or, h = 450/(πr²) ... (i).

The cost of the microwaveable cup-of-soup package is given as:

The bottom is made of styrofoam at 0.03 cents/cm².

The area of the bottom = πr².

Therefore, the cost of the bottom = πr²(0.03) cents.

The side is made of styrofoam at the rate of 0.03 cents/cm².

The area of the side = 2πrh = 2πr{450/(πr²)}. {Taking h = 450/(πr²) from (i)}.

Therefore, the cost of the side = 2πr{450/(πr²)}(0.03) cents.

The top is made of glued paper at the rate of 0.08 cents/cm².

The area of the top = πr².

Therefore, the cost of the top = πr²(0.08) cents.

Therefore the total production cost function can be written as:

C = πr²(0.03) + 2πr{450/(πr²)}(0.03) + πr²(0.08) cents,

or, C = 0.03πr² + 0.08πr² + 27/r cents,

or, C = 0.11πr² + 27/r cents ... (ii).

We are asked to minimize the cost function.

To minimize it, we follow these steps:

Differentiating both sides in (ii) with respect to the radius,

dC/dr = 0.22πr - 27/r² ... (iii).

To get the points of inflections, we equate this to zero, to get,

dC/dr = 0.22πr - 27/r² = 0,

or, 0.22πr - 27/r² = 0,

or, 0.22πr = 27/r²,

or, r³ = 27/0.22π,

or, r = ∛(27/0.22π) = 3.393 cm.

To check whether the cost C, is minimum or maximum at the point, we calculate the second order differential, and if it's greater than 0, then we get a minimum and vice-versa.

Thus, differentiating both sides of (iii), with respect to the radius r, we get:

d²C/dr² = 0.22π + 54/r³.

0.22π + 54/r³ is greater than 0, for all values of r, since r is always greater than 0 {radius of an object cannot be negative}.

Thus, the radius at which the cost is minimized is 3.393 cm.

The corresponding height will be 450/(πr²) = 9.274 cm.

Thus, the dimensions of the microwave cup-of-soup package are:

Radius = 3.39cm, and Height = 9.27cm.

Computed using differentiation.

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