y=-3x² + 12x - 12 has how many real roots?
A. 0
B. 1
C. cannot be determined
D. 2

The equation has 2 real roots
The equation is given as:
[tex]y = 3x^2 + 12x - 12[/tex]
Calculate the determinant using
d = b^2 - 4ac
So, we have:
d = 12^2 - 4 * 3 * (-12)
Evaluate
d = 288
Because d > 0
i.e. 288 is greater than 0
Then it means that the equation has 2 real roots
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