The correct options, in order, are:
[tex]f(n) = 3*(2)^{n-1}[/tex]
[tex]f(n) = 2*(6)^{n - 1}[/tex]
[tex]f(n) = 2*(4)^{n - 1}[/tex]
How to match the equations and the tables?
The first table is:
n f(n)
1 3
2 6
3 12
Notice that when n = 1, all the exponents are 0, then the initial value is 3.
When n = 2, all the exponents are 1. Then we need to find the exponential equation with a base equal to 2.
So the exponential equation is:
[tex]f(n) = 3*(2)^{n-1}[/tex]
The second table is:
n f(n)
1 2
2 12
3 72
By looking at the first pair, we conclude that the initial value is 2, and by looking at the second pair, we conclude that:
2*b = 12
b = 12/2 = 6
The base is 6.
So the exponential equation now is:
[tex]f(n) = 2*(6)^{n - 1}[/tex]
The last table is:
n f(n)
1 2
2 8
3 32
Here we again have an initial value of 2, and the base is:
2*b = 8
b = 8/2 = 4
Then the correct option now is:
[tex]f(n) = 2*(4)^{n - 1}[/tex]
If you want to learn more about exponential equations:
https://brainly.com/question/11832081
#SPJ1
