Answer: (1,2)
Step-by-step explanation:
I will help you..
Given:
[tex]-2x-5y=-12\\10x-4y=2[/tex]
Lets cancel out the x term..
[tex]5(-2x-5y)=-12(5)\\=-10x-25y=-60[/tex]
Now our system looks like this:
[tex]-10x-25y=-60\\10x-4y=2[/tex]
Add.
[tex]-29y=-58\\y=2[/tex]
plug in 2 for y
[tex]-2x-5(2)=-12\\-2x-10=-12\\-2x=-2\\x=1[/tex]
Therefore the system is:
[tex](1, 2)[/tex]
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