The pressure on the diver is given by:
[tex] p=\frac{F}{A} [/tex]
where F is the force exerted by the water on the diver, while A is the area of the diver.
In this problem, we know the pressure: [tex] p=202 kPa=2.02 \cdot 10^5 Pa [/tex], and the area of the diver, [tex] A=1.50 m^2 [/tex], therefore we can rearrange the initial equation to find the force on the diver:
[tex] F=pA=(2.02 \cdot 10^5 Pa)(1.50 m^2)=3.03 \cdot 10^5 N [/tex]
The total force applied by the water of the driver is [tex]\bold {3.03 \times 10^5 \rm \ N}[/tex]. Force can be defined as the product of the pressure and surface area of the object and body.
Force can be defined as the product of the pressure and surface area of the object and body.
[tex]F = pA[/tex]
Where,
[tex]F[/tex] = Force
[tex]p[/tex] - pressure = 202 kPa = [tex]2.02 \times 10^5[/tex] Pa.
[tex]A[/tex] - surface area = 1.50 m²
Put the values in the formula,
[tex]F = 2.02 \times 10^5\times 1.5 \\\\F = 3.03 \times 10^5[/tex]
Therefore, the total force applied by the water of the driver is [tex]\bold {3.03 \times 10^5 \rm \ N}[/tex].
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